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The convolution square of a differentiable function need not be differentiable
2020
Colloquium Mathematicum
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The convolution product of a differentiable function with itself may fail to be Hölder continuous of any index on a dense set of points. E n =
doi:10.4064/cm7894-6-2019
fatcat:sasvkp3xxzba5aopvh4etq5j3u