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Sullivan's de Rham complex is definable in terms of its $0$-forms
1976
Proceedings of the American Mathematical Society
It is proved that for a simplicial complex Sullivan's de Rham complex is definable in terms of its 0-forms.
doi:10.1090/s0002-9939-1976-0410737-2
fatcat:2ntj6hfkvvd3dls3hv37v5t6pq