Discussion: "Regulation of a Hydraulic Turbine Calculated by Step-By-Step Method" (Swiecicki, Ignacy, 1961, ASME J. Basic Eng., 83, pp. 445–450)

C. L. Avery
1961 Journal of Basic Engineering  
0.250 \ AW = -0.153 (0.99 X 0 + 0.456 -h 1 -1 j = -0.017 At T = 0.2 sec W = 0 -0.017 = -0.017 During the first time interval mean W = 1/2(0 -0.017) = -0.0085 As = -0.0085 X 0.2 = -0.002 At T = 0.2 sec s = 0.591 -0.002 = 0.589 Prom Fig. 2 for s •= 0.589 we have pi = 0.748; q, = 0.767 Aq, = 0.767 -0.769 = -0.002, 2 X 1 X (-0.002) Ah ^ = 0.004 0.273 V 1 + 0.767 At T = 0.2 sec h = 1 + 0.004 = 1.004 p = 0.748 X 1.004 X VHOOi = 0.753 mean p = 1/2 (0.750 + 0.753) = 0.7515 0.7515 -0.500 An = 0.0247 = 0.0062 At IT = 0.2 sec 1 n = 1 + 0.0062 = 1.0062
doi:10.1115/1.3658994 fatcat:643pmcuns5gddd63per7khmkim